Answer
Doesn't make sense.
Work Step by Step
Exponential growth and decay models are given by $A=A_{0}e^{kt}$
in which $t$ represents time,
$A_{0}$ is the amount present at $t=0$, and
$A$ is the amount present at time $t$.
If $k > 0$, the model describes growth and $k$ is the growth rate.
If $k < 0$, the model describes decay and $k$ is the decay rate.
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Let
$A_{1}=A_{0}e^{0.01t}$ be the model for growth with $ 1\%$ growth rate.
and
$A_{3}=A_{0}e^{0.03t}$ be the model for growth with $ 3\%$ growth rate.
In 100 years time (t=100), the ratio of populations will be
$\displaystyle \frac{A_{3}}{A_{1}}=\frac{A_{0}e^{0.03(100)}}{A_{0}e^{0.01(100)}}=\frac{e^{3}}{e^{1}}=e^{2}\approx$7.38905609893
so,
$A_{3}\approx 7.4A_{1}$,
meaning that
the population with $ 3\%$ growth rate will be about 7.4 times greater than the one with $ 1\%$ growth rate.
