Answer
False
Work Step by Step
$$\log(x + 3) = 2$$ $$\log_{10}(x + 3) = 2$$ $$10^2 = x+3$$ $$100 – 3 = 97 = x$$ Therefore, $[\log(x+3) = 2] \neq [e^2 = x + 3]$ since both logarithmic bases are dissimilar.
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 493: 141
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