Answer
$x=2$
Work Step by Step
We are given the exponential equation $4^{2x-1}=64$.
We can express each side using a common base and then solve for $x$.
$4^{2x-1}=4^{3}=64$
Take the natural log of both sides.
$ln(4^{2x-1})=ln(4^{3})$
$(2x-1)ln(4)=3ln(4)$
Divide both sides by $ln(4)$.
$2x-1=3$
Add 1 to both sides.
$2x=4$
Divide both sides by 2.
$x=2$
