Answer
a. $\$ 9479.19$
b. $\$ 9527.79$
c. $\$ 9560.92$
d. $\$ 9577.70$
Work Step by Step
After $t$ years, the balance, $A$,
in an account with principal $P$
and annual interest rate $r$ (in decimal form)
is given by one of the following formulas:
1. For $n$ compoundings per year: $A=P(1+\displaystyle \frac{r}{n})^{nt}$
2. For continuous compounding: $A=Pe^{rt}$.
------------------------
$\mathrm{a}$.
$ A=5000(1+\displaystyle \frac{0.065}{2})^{2\cdot 10}\approx \$ 9479.19$
$\mathrm{b}$.
$A=5000(1+\displaystyle \frac{0.065}{4})^{4\cdot 10}\approx\$ 9527.79$
$\mathrm{c}$.
$A=5000(1+\displaystyle \frac{0.065}{12})^{12\cdot 10}\approx\$ 9560.92$
$\mathrm{d}$.
$A=5000(e)^{0.065\cdot 10}\approx\$ 9577.70$