College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 3 - Summary, Review, and Test - Test - Page 439: 4


See below.

Work Step by Step

The maximum value is at $x=-\frac{b}{2a}=-\frac{46}{2\cdot(-1)}=23.$ Hence the maximum value is $f(23)=-(23)^2+46(23)-360=169.$
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