Answer
$(10x^3-26x^2+17x-13)\div(5x-3)=2x^2-4x+1-\frac{10}{5x-3}$
Work Step by Step
$\begin{array}{lllll}
& 2x^{2} & -4x & +1 & \\
& -- & -- & -- & -\\
5x-3\ \ \ \ \ ) & 10x^{3} & -26x^{2} & +17x & -13\\
& -10x^{3} & +6x^{2} & & \\
& -- & -- & & \\
& & -20x^{2} & +17x & \\
& & +20x^{2} & -12x & \\
& & -- & -- & \\
& & & 5x & -13\\
& & & -5x & +3\\
& & & -- & --\\
& & & & -10
\end{array} $
$(10x^3-26x^2+17x-13)\div(5x-3)=2x^2-4x+1-\frac{10}{5x-3}$
