College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 3 - Summary, Review, and Test - Review Exercises - Page 435: 8

Answer

Dimensions: ($250$ yd)$\times$ ($500$ yd) Area: $125,000$ square yards.

Work Step by Step

The area A = (width)$\times$(length), $A=x(1000-2x)=1000x-2x^{2}$ As a function of x, $A(x)=-2x^{2}+1000x$ is a quadratic function, $A(x)=ax^{2}+bx+c$. whose graph is a parabola that opens down, since $a=-2$, negative. Its vertex is a maximum point, which occurs at $x=-\displaystyle \frac{b}{2a}=-\frac{1000}{2(-2)}=250$ yd. So, the dimensions of the field of greatest area are ($250$ yd)$\times$ ($1000-2\cdot 250$ yd) $= $($250$ yd)$\times$ ($500$ yd) The area of that rectangle is $A(250)=125,000$ square yards.
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