Answer
Vertical asymptote: none
Hole at $x=-6$
Work Step by Step
Locating Vertical Asymptotes, (page 395) tells us that for $f(x)=\displaystyle \frac{p(x)}{q(x)}$,
if p(x) and q(x) have NO common factors,
and a is a zero of the denominator $q(x)$ ,
then the line $x=a$ is a vertical asymptote.
BUT, if they DO have common factors,
after REDUCING the form of the function's equation,
the number a may not cause the denominator to be zero any more.
in which case there will be a hole at x=a.
The point is that both p(x) and q(x) have to be factored,
and if we can, then we reduce the expression for f(x).
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$r(x)=\displaystyle \frac{x^{2}+2x-24}{x+6}$
$p(x)=x^{2}+4x-24$
(find two factors of $-24$ whose sum is +$2$ ...
...found $+6$ and $-4$ )
$p(x)=(x+6)(x-4)$
$q(x)=x+6\qquad $... fully factored
We can reduce the expression for $r(x):$
$r(x)=\displaystyle \frac{x^{2}+2x-24}{x+6}\\=\dfrac{(x+6)(x-4)}{ (x+6)}=x-4,\quad x\neq-6$
Vertical asymptote: none
Hole at $x=-6$
