College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 3 - Polynomial and Rational Functions - Exercise Set 3.3 - Page 375: 54

Answer

$l=8x^2-12x+4$

Work Step by Step

The Area of the rectangle is, $A=l \times w$, whereas $l$ is a length of the rectangle and $w$ is the width of the rectangle. To find the the length $l$, we can divide both sides of the formula by $w$. $A/w=l$. Therefore, $\begin{array}{lllll} \underline{-3/4}| & 8 & -6 & -5 & 3\\ & & -6 & 9 & -3\\ \hline & & & & \\ & 8 & -12 & 4 & 0 \end{array}$ $(8x^{3}-6x^2-5x+3)\div(x+3/4)=8x^2-12x+4$. There by dividing the area by width we can get the length. $l=8x^2-12x+4$
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