Answer
$y=A(x-1)^2+2,A>0$
Work Step by Step
Vertex=$(1,2)$
-It is an upward opening parabola
-Since it opens upward and the minimum point(the vertex) is at $(1,2)$, the parabola has no x-intercept
-Since it opens upward. The leading coefficient of the function of the parabola is positive
-Since we have the equation of the parabola, $x=-b/2a=1=-b=2a$
-Equation of the parabola is of the form of $A(x-1)^2+2$, whereas $A$ is the leading coefficient and it is positive
