## College Algebra (6th Edition)

Published by Pearson

# Chapter 3 - Polynomial and Rational Functions - Exercise Set 3.1 - Page 344: 51

#### Answer

f(x)=2(x+10)$^2$-5

#### Work Step by Step

The given function has its vertex at 0. To move the vertex to (-10,-5) you must subtract negative ten from x and add negative five to the function. This gives you f(x)=2(x+10)$^2$-5.

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