Answer
$x= -\frac{b}{2a}$ , $f(-\frac{b}{2a})$
$x= -\frac{b}{2a}$ , $f(-\frac{b}{2a})$
Work Step by Step
Consider the quadratic function $f(x)=ax^{2}+bx+c, a\ne0.$
If a > 0, then f has a minimum that occurs at $x= -\frac{b}{2a}$. This minimum value is $f(-\frac{b}{2a})$. If a < 0, then f has a maximum that occurs at $x= -\frac{b}{2a}$. This maximum value is $f(-\frac{b}{2a})$.