College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Summary, Review, and Test - Test - Page 328: 34

Answer

(a) Length = $5$ (b) Mid-point = $(\frac{7}{2}, 0)$

Work Step by Step

(a) Length formula: $\sqrt{(y_{2}-y_{1})^2 + (x_{2} - x_{1})^2}$, therefore: $$\sqrt{(2-(-2))^2 + (5 - 2)^2}$$ $$\sqrt{(4)^2 + (3)^2}$$ $$\sqrt{16 + 9}$$ $$\sqrt{25}$$ $$5$$ (b) Mid-point formula: $(\frac{x_{2} + x_{1}}{2}, \frac{y_{2} + y_{1}}{2})$, therefore: $$(\frac{5 + 2}{2}, \frac{2 + -2}{2})$$ $$(\frac{7}{2}, 0)$$
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