Answer
$10$
Work Step by Step
If $f(x)=x^2-4x$, then $\frac{f(x+h)-f(x)}{h}=\frac{(x+h)^2-4(x+h)-(x^2-4x)}{h}=\frac{x^2+2xh+h^2-4x-4h-x^2+4x}{h}=\frac{2xh+h^2-4h}{h}=2x+h-4$
$h=9-5=4,x=5$, thus our expression evaluates to $2\cdot5+4-4=10$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 2 - Summary, Review, and Test - Review Exercises - Page 325: 48
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