College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Summary, Review, and Test - Review Exercises - Page 323: 10

Answer

a.) f(-2)=-1 b.) f(1)=12 c.) f(2)=3

Work Step by Step

a.) f(-2)=$\frac{(-2)^2-1}{(-2)-1}$ f(-2)=$\frac{3}{-3}$ f(-2)=-1 b.) f(1)=12 c.) f(2)=$\frac{(2)^2-1}{(2)-1}$ f(2)=$\frac{3}{1}$ f(2)=3
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