College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Mid-Chapter Check Point - Page 270: 42

Answer

y=-2.5x-13

Work Step by Step

2x-5y-10=0 5y=2x-10 y=$\frac{2}{5}$x-2 Therefore the desired line as a slope of m=-$\frac{5}{2}$=-2.5 y-(-3)=-2.5(x-(-4)) y+3=-2.5x-10 y=-2.5x-13
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