College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.8 - Page 321: 98

Answer

$x = 5$ or $x = 1$

Work Step by Step

$$-2(x-3)^2 + 8 =0$$ $$-2(x-3)^2 =-8$$ $$\sqrt{(x-3)^2} = \sqrt{4}$$ $$x-3 = \frac{+}{}2$$ $$x = 3 \frac{+}{} 2$$ $$x = 5$$ $$or$$ $$x = 1$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.