Answer
$x^2+(y-82)^2=68^2$
Work Step by Step
The standard form of equation of a circle is: $(x-a)^2+(y-b)^2=r^2$ where $(a,b)$ is the center of the circle and $r$ is the radius.
Hence here $r=68$, $a=0$, $b=14+68=82$ by the text of the exercise, thus the equation is: $x^2+(y-82)^2=68^2$
