College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.2 - Page 243: 122

Answer

$3$

Work Step by Step

$(x_1,y_1)=(-3,1),(x_2,y_2)=(-2,4)$, thus $x_1=-3,x_2=-2,y_1=1,y_2=4$, hence $\frac{y_2-y_1}{x_2-x_1}=\frac{4-1}{-2-(-3)}=\frac{3}{1}=3$
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