College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 2 - Functions and Graphs - Exercise Set 2.2 - Page 240: 42


a. $12$ b. $5$ c. $10$

Work Step by Step

a. x=7$\neq$5, so we calculate $h(7)$ using the $\displaystyle \frac{x^{2}-25}{x-5}$ part $h(7)=\displaystyle \frac{7^{2}-25}{7-5}=\frac{49-25}{2}=\frac{24}{2}=12$ b. x=$ 0\neq$5, so we calculate $h(0)$ using the $\displaystyle \frac{x^{2}-25}{x-5}$ part $h(7)=\displaystyle \frac{0^{2}-25}{0-5}=\frac{ -25}{-5}=5$ c. for $x=5, h(5)=10$
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