Answer
a. $12$
b. $5$
c. $10$
Work Step by Step
a.
x=7$\neq$5, so we calculate $h(7)$ using the $\displaystyle \frac{x^{2}-25}{x-5}$ part
$h(7)=\displaystyle \frac{7^{2}-25}{7-5}=\frac{49-25}{2}=\frac{24}{2}=12$
b.
x=$ 0\neq$5, so we calculate $h(0)$ using the $\displaystyle \frac{x^{2}-25}{x-5}$ part
$h(7)=\displaystyle \frac{0^{2}-25}{0-5}=\frac{ -25}{-5}=5$
c. for $x=5, h(5)=10$
