Answer
This function is even.
Work Step by Step
$f(x)=x^{2}\sqrt{1-x^{2}}$
Substitute $x$ by $-x$ in $f(x)$ and simplify:
$f(-x)=(-x)^{2}\sqrt{1-(-x)^{2}}=x^{2}\sqrt{1-x^{2}}$
Since $f(-x)=f(x)$, this function is even.
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