## College Algebra (6th Edition)

$[59,95]$
Use the given information in the problem to create an inequality based on the original equation. Then multiply $\frac{9}{5}$, and add $32$ on all three sides to solve for $F$. $C=\frac{5}{9}(F-32)$ $15\leq C\leq35$ $15\leq\frac{5}{9}(F-32)\leq35$ $27\leq(F-32)\leq63$ $59\leq F\leq95$