College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.7 - Page 198: 120



Work Step by Step

Use the given information in the problem to create an inequality based on the original equation. Then multiply $\frac{9}{5}$, and add $32$ on all three sides to solve for $F$. $C=\frac{5}{9}(F-32)$ $15\leq C\leq35$ $15\leq\frac{5}{9}(F-32)\leq35$ $27\leq(F-32)\leq63$ $59\leq F\leq95$
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