College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.1 - Page 105: 88

Answer

$-x+10$

Work Step by Step

Distribute to multiply $12$ by the terms inside the parentheses. Then divide to get rid of the fractions. Then distribute to multiply again and simplify. $12(\frac{x+2}{4}-\frac{x-1}{3})$ $\frac{12(x+2)}{4}-\frac{12(x-1)}{3}$ $3(x+2)-4(x-1)$ $3x+6-4x+4$ $-x+10$
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