## College Algebra (6th Edition)

Consider the equation $$\sqrt{2x+1}=x-7$$ Squaring the left side and simplifying results in $2x+1$ Squaring the right side and simplifying results in $x^{2}-14x+49$
The equation given is $$\sqrt{2x+1}=x-7$$ Squaring the left side of the equation results in the elimination of the square root, so the first answer is: $(\sqrt{2x+1})^{2}=2x+1$ The right side is a binomial, squaring it and simplifying it produces a trinomial, which is: $(x-7)^{2}=x^{2}-14x+49$