College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Test - Page 78: 25



Work Step by Step

Getting the factors that are perfect roots of the index, the given expression, $ \sqrt{18x^5y^8} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt{9x^4y^8\cdot2x} \\\\= \sqrt{(3x^2y^4)^2\cdot2x} \\\\= 3x^2y^4\sqrt{2x} .\end{array} Note that the variables are assumed to contain positive real numbers.
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