College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.7 - Radical Expressions - R.7 Exercises - Page 69: 106

Answer

$19$ degrees Fahrenheit

Work Step by Step

Given: Wind chill = $35.74+0.6215\cdot T -35.75\cdot V^{0.16} +0.4275\cdot T\cdot V^{.16}$ $T=30$ degrees Fahrenheit $V=15$ mph wind Substitute the given values if $V$ and $T$ into the formula above to obtain $\text{Wind chill temperature} = 35.74+0.6215\cdot 30 -35.75\cdot 15^{0.16} +0.4275\cdot30\cdot15^{0.16}$ $\text{Wind chill temperature} = 35.74 + 18.645 – 35.75\cdot1.542320395 + 12.825\cdot1.542320395$ $\text{Wind chill temperature} = 19.02730495$ $\text{Wind chill temperature} \approx 19$
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