College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.7 - Radical Expressions - R.7 Exercises - Page 68: 70

Answer

$11\sqrt{2k}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To add/subtract the given expression, $ 4\sqrt{18k}-\sqrt{72k}+\sqrt{50k} ,$ simplify first each radical term by extracting the factor that is a perfect power of the index. Then, combine the like radicals. $\bf{\text{Solution Details:}}$ Extracting the factors of each radicand that is a perfect power of the index results to \begin{array}{l}\require{cancel} 4\sqrt{9\cdot2k}-\sqrt{36\cdot2k}+\sqrt{25\cdot2k} \\\\= 4\sqrt{(3)^2\cdot2k}-\sqrt{(6)^2\cdot2k}+\sqrt{(5)^2\cdot2k} \\\\= 4(3)\sqrt{2k}-6\sqrt{2k}+5\sqrt{2k} \\\\= 12\sqrt{2k}-6\sqrt{2k}+5\sqrt{2k} .\end{array} By combining the like radicals, the expression above simplifies to \begin{array}{l}\require{cancel} (12-6+5)\sqrt{2k} \\\\= 11\sqrt{2k} .\end{array}
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