College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.6 - Rational Exponents - R.6 Exercises - Page 56: 7

Answer

9

Work Step by Step

Rewrite the negative exponent taking the reciprocal of the value. Then evaluate the exponent. $\frac{1}{(\frac{1}{3})^2}=\frac{1}{\frac{1}{9}}=9$
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