College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.3 - Polynomials - R.3 Exercises - Page 31: 105

Answer

The polynomial value is lower than the graph value by $0.3$

Work Step by Step

1. Evaluate the polynomial: $0.001147x^2 - 4.5905x + 4595$ at the value $x = 1990$. $0.001147x^2 - 4.5905x + 4595 = .001147 \cdot (1990^2) - 4.5905 \cdot 1990 + 4595$ This gives $4542.2 - 9135.1 + 4595 $ which equals approximately $2.1$. 2. The value in the graph corresponding to $1990$ is $2.4$. Comparing the value of the polynomial to the value in the graph we find that the value of the polynomial is lower by $2.4-2.1=0.3$ than the value in the graph.
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