College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.3 - Polynomials - R.3 Exercises: 74



Work Step by Step

Using $(a\pm b)^3=a^3\pm3a^2b+3ab^2\pm b^3$ or the cube of a binomial, the expression, $ (z-3)^3 ,$ is equivalent to \begin{array}{l}\require{cancel} (z)^3-3(z)^2(3)+3(z)(3)^2-(3)^3 \\\\= z^3-3(z^2)(3)+3(z)(9)-27 \\\\= z^3-9z^2+27z-27 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.