College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.3 - Polynomials - R.3 Exercises - Page 28: 20

Answer

$\frac{-125n^{12}}{r^{6}}$

Work Step by Step

$(\frac{-5n^{4}}{r^{2}})^{3}$ = $\frac{(-5n^{4})^{3}}{(r^{2})^{3}}$ = $\frac{(-5)^{3}n^{4*3}}{r^{2*3}}$ = $\frac{-125n^{12}}{r^{6}}$
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