College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.2 - Real Numbers and Their Properties - R.2 Exercises - Page 20: 132

Answer

$\text{Rating }\approx 91.0 $

Work Step by Step

Using the given formula, $ \text{Rating = }\dfrac{\left(250\cdot\dfrac{C}{A} \right)+\left(1000\cdot\dfrac{T}{A} \right)+\left(12.5\cdot\dfrac{Y}{A} \right)+6.25-\left(1250\cdot\dfrac{I}{A} \right)}{3} ,$ where $A= 658 ,$ $C= 448 ,$ $T= 33 ,$ $Y= 4620 ,$ and $I= 22 ,$ then \begin{array}{l}\require{cancel} \text{Rating = } \dfrac{\left(250\cdot\dfrac{ 448 }{ 658 } \right)+\left(1000\cdot\dfrac{ 33 }{ 658 } \right)+\left(12.5\cdot\dfrac{ 4620 }{ 658 } \right)+6.25-\left(1250\cdot\dfrac{ 22 }{ 658 } \right)}{3} \\\\ \text{Rating = } 90.86246 \\\\ \text{Rating }\approx 91.0 .\end{array}
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