## College Algebra (11th Edition)

$0.031$
We will use the following formula for the blood alcohol concentration (BAC) of a person who has been drinking. BAC = (number of oz)(% alcohol)(0.075) / (body weight in lb) - (hr of drinking)(0.015). We are to determine the BAC for a 190 lb man who has ingested four 12-oz-beers (48 oz) each having 3.2% alcohol, in 2 hours. Estimate to the nearest thousandth. Number of oz = 48 % alcohol = 3.2 body weight = 190 hr of drinking = 2 We will use the formula: $BAC=(48)(3.2)(0.075)\div(190)-(2)(0.015)$ $=11.52\div190-2(0.015)$ $=0.061-0.03$ Therefore, the BAC of the person is: $BAC=0.061-0.03=0.031$