College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.2 - Real Numbers and Their Properties - R.2 Exercises: 117

Answer

$0.031$

Work Step by Step

We will use the following formula for the blood alcohol concentration (BAC) of a person who has been drinking. BAC = (number of oz)(% alcohol)(0.075) / (body weight in lb) - (hr of drinking)(0.015). We are to determine the BAC for a 190 lb man who has ingested four 12-oz-beers (48 oz) each having 3.2% alcohol, in 2 hours. Estimate to the nearest thousandth. Number of oz = 48 % alcohol = 3.2 body weight = 190 hr of drinking = 2 We will use the formula: $BAC=(48)(3.2)(0.075)\div(190)-(2)(0.015)$ $=11.52\div190-2(0.015)$ $=0.061-0.03$ Therefore, the BAC of the person is: $BAC=0.061-0.03=0.031$
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