## College Algebra (11th Edition)

(a) $P(H)=1$ (b) $P(T)=0$
The sample set is $S=${$H$}, therefore the total number of outcomes is 1. The probalitity of an event can be calculated as: $P(A)=\frac{\text{favorable outcomes out of the sample set}}{\text{total number of possible outcomes}}$ This means, that the probability of the event that the toss is heads is 1, as there is one favorable outcome out of the sample set: $P(H)=\frac{1}{1}=1$ The probability of the event that the toss is tails is 0, as there isn't any favorable outcome out of the sample set: $P(T)=\frac{0}{1}=0$