College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 7 - Section 7.4 - The Binomial Theorem - 7.4 Exercises - Page 664: 10

Answer

1

Work Step by Step

Using the formula of ${n}\choose{k}$$=\frac{n!}{k!(n-k)!}$ where $n=k=15$: ${15}\choose{15}$=$\frac{15!}{15!0!}$ By definition: $0!=1$, therefore, ${15}\choose{15}$=$\frac{15!}{15!}=1$
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