Answer
$3,628,880$
Work Step by Step
Definition of a factorial $n!=n(n-1)(n-2)\cdot...\cdot3\cdot2 \cdot 1$
Therefore, we have:
$10(9!)=10 \cdot 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1=3,628, 880$
College Algebra (11th Edition)
by Lial, Margaret L.; Hornsby John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671791
ISBN 13:
978-0-32167-179-0
Chapter 7 - Review Exercises - Page 699: 60
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