College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 6 - Review Exercises - Page 623: 10

Answer

$x^2=- 12y$

Work Step by Step

Here, the focus is below the origin and the focus $(0,-3)$ refers to $p=-3$. The standard form of a vertical parabola is given as: $x^2=4py$ when the parabola with vertical axis of symmetry. Now, we will plug the value of $p=-3$ in the standard form of parabola to obtain: $x^2 =(4)(-3) y \implies x^2=- 12y$ Hence, the required equation of the parabola is: $x^2=- 12y$
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