College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Section 5.8 - Matrix Inverses - 5.8 Exercises - Page 565: 3

Answer

The given matrices are inverses of each other.

Work Step by Step

We know that when two matrices $P$ and $Q$ are two $n\times n$ matrices so that $PQ=QP=I_n$, then $P$ and $Q$ are inverses of each other. Here, we have: $P=\begin{bmatrix} 5 & 7 \\ 2 & 3 \end{bmatrix}$ and $Q=\begin{bmatrix} 3 & -7 \\ -2 & 5 \end{bmatrix} $ . As we can see that both matrices of the same dimensions, that is, $2 \times 2$ or, $n=2$. Thus, we can multiply them easily. $PQ=\begin{bmatrix} 5 & 7 \\ 2 & 3 \end{bmatrix} \begin{bmatrix} 3 & -7 \\ -2 & 5 \end{bmatrix}\\ =\begin{bmatrix} (5)(3) +(7)(-2) & (5)(-7) +(7)(5) \\ (2)(3) +(3)(-2)& (2)(-7) +(3)(5) \end{bmatrix} \\\\=\begin{bmatrix} 1 & 0 \\ 0& 1 \end{bmatrix} $ This implies that the given matrices are inverses of each other because $PQ= I_2$, that is, their products shows an identity matrix.
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