Answer
$(1,1);(-2,4)$
Work Step by Step
$$\begin{cases} x^2-y=0\\x+y=2 \end{cases}$$
Add both equations:
$$x^2-y+x+y=0+2$$
$$x^2+x-2=0$$
$$(x+2)(x-1)=0$$
$$x=-2~~~or~~~x=1$$
Find corresponding $y$ values for each $x$ values:
$$-2+y=2\to y=4$$
$$1+y=2\to y=1$$
Solutions are:
$$(1,1);(-2,4)$$
