College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Section 5.1 - Systems of Linear Equations - 5.1 Exercises - Page 487: 34

Answer

The system of equations has infinitely many solutions . Solution set: $\left\{\left(\dfrac{-2-5y}{3}, \dfrac{-6-15y}{9}\right)\right\}$

Work Step by Step

We need to solve the given system of equations: $$3x+5y=-2 ~~~(1) \\ 9x+15y=-6 ~~~(2)$$ Multiply the first equation by $-3$ to obtain the equivalent equation: $$-9x-15y=6 ~~~~(3)$$ Add equations (2) and (3) to eliminate $x$. $$9x+15y-9x-15y=-6+6 \\ 0=0 $$ Both variables were eliminated and resulted in a true equation/statement. This means that the system has infinitely many solutions. Solve for $x$ in the first equation to obtain: \begin{align*} 3x+5y&=-2\\ 3x&=-5y-2\\ x&=\dfrac{-5y-2}{3} \end{align*} Thus, the solution set is $\left\{\left(\dfrac{-2-5y}{3}, \dfrac{-6-15y}{9}\right)\right\}$.
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