Answer
Domain: $x\in (-\infty,-\sqrt7)\cup(-\sqrt7,\sqrt7)\cup(\sqrt7,\infty)$
Work Step by Step
For a rational function, domain is all real numbers except for which denominator is zero.
For the given function, denominator is zero when:
$$|x^2-7|=0$$
$$x^2-7=0$$
$$x^2=7$$
$$x=\pm\sqrt{7}$$
Hence, the domain is:
$$x\in (-\infty,-\sqrt7)\cup(-\sqrt7,\sqrt7)\cup(\sqrt7,\infty)$$
