College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.4 - Evaluating Logarithms and the Change-of-Base Theorem - 4.4 Exercises - Page 435: 55

Answer

$\approx2.0200$

Work Step by Step

$\ln\left(\dfrac{98}{13}\right)$ Using the quotient property of logarithms: $\ln98-\ln13\approx 4.58497-2.56495\approx2.0200$
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