Chapter 4 - Section 4.2 - Exponential Functions - 4.2 Exercises - Page 412: 101

$x \approx 0.9$ See the picture below

Divide 5 on both sides of the equation: $\dfrac{5e^{3x}}{5}=\dfrac{75}{5}$ $e^{3x}=15$ Here, we have to graph functions on the two sides of the equation. So by graphing the functions $f(x)=e^{3x}$ and $g(x)=15$ (refer to the attached image), we can see that, there is one intersection point, therefore there will be one solution. This is: $x\approx0.9$