## College Algebra (11th Edition)

The two functions are inverses of each other if $(f\circ g)(x)=(g\circ f)(x)$. For the given functions, $(f\circ g)(x) \\=f(g(x) \\=-4(-\frac{1}{4}x-2)+2 \\=x+8+2 \\=x+10$ Therefore, $f$ and $g$are not inverses of each other.