College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.1 - Inverse Functions - 4.1 Exercises - Page 394: 18

Answer

The function is not one to one.

Work Step by Step

Notice that the graph of this function does not pass the horizontal line test, because it is possible to draw a horizontal line that passes through the graph more than once, as shown in red. This means the function is not one-to-one. $-3((6\sqrt{\frac{8}{3}})-6)^2+8=0=-3((6\sqrt{\frac{8}{3}})-6)^2+8$ Equivalently, notice that it is possible to find two different $x$ values that have the same $y$ value ($x=6+\sqrt{\frac{8}{3}}$ and $x=6+\sqrt{\frac{8}{3}}$ both have $y$ value 0). This means the function is not one-to-one.
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