## College Algebra (11th Edition)

$\approx1.1592$
By using the change of base formula we can calculate easily the value of $\log_{\frac{2}{3}}\frac{5}{8}$. $\log_{\frac{2}{3}}\frac{5}{8}=\frac{\log_{10}\frac{5}{8}}{\log_{10}\frac{2}{3}}\approx1.1592$