College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Review Exercises - Page 469: 33



Work Step by Step

By using the change of base formula we can calculate easily the value of $\log_{\frac{2}{3}}\frac{5}{8}$. $\log_{\frac{2}{3}}\frac{5}{8}=\frac{\log_{10}\frac{5}{8}}{\log_{10}\frac{2}{3}}\approx1.1592$
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