College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Quiz - Sections 4.1-4.4 - Page 439: 10

Answer

$7.8137$

Work Step by Step

Using properties of logarithm: $$\log_b 225=\log_b (9\cdot5\cdot5)=\log_b 9+\log_b 5+\log_b 5=$$ $$=3.1699+2.3219+2.3219=7.8137$$
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