Answer
The vertex is (2,0).
The axis is x=2.
The domain is $(-\infty,\infty)$.
The range is $[0,\infty)$
The function is increasing on $[2,\infty)$.
The function is decreasing on $(-\infty, 2)$.
Work Step by Step
The equation is in form $y=a(x-h)^2+k$
The vertex is (h,k).
The vertex is (2,0).
The axis is x=h.
The axis is x=2.
The domain is $(-\infty,\infty)$.
The range is $[0,\infty)$, since there will never be a coordinate with a negative y-value.
The function is increasing on $[2,\infty)$, since a>0.
The function is decreasing on $(-\infty, 2)$, since a>0.
