Answer
$(x+1)$ is a factor
Work Step by Step
Using Factor theorem, $(x+1)$ is a factor of $f(x)$ if $f(-1)=0$.
Check this condition:
$$f(-1)=(-1)^3+2(-1)^2+3(-1)+2=$$ $$=-1+2\cdot1-3+2=0$$ Hence, $(x+1)$ is indeed a factor.
College Algebra (11th Edition)
by Lial, Margaret L.; Hornsby John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671791
ISBN 13:
978-0-32167-179-0
Chapter 3 - Review Exercises - Page 377: 43
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