Answer
$(g\circ f)(3)=0$
Work Step by Step
The given functions:
$$f(x)=2x-3~~~~~~~~g(x)=-x+3$$
Composition of functions:
$$(g\circ f)(x)=g(f(x))=-(2x-3)+3=$$
$$=-2x+3+3=-2x+6$$
Substitute $x=3$ in composition:
$$(g\circ f)(3)=-2\cdot3+6=0$$