College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.8 - Function Operations and Composition - 2.8 Exercises - Page 268: 50

Answer

$(g\circ f)(3)=0$

Work Step by Step

The given functions: $$f(x)=2x-3~~~~~~~~g(x)=-x+3$$ Composition of functions: $$(g\circ f)(x)=g(f(x))=-(2x-3)+3=$$ $$=-2x+3+3=-2x+6$$ Substitute $x=3$ in composition: $$(g\circ f)(3)=-2\cdot3+6=0$$
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